Outlook asking for password again and again…

Why outlook asks for password frequently?

Outlook asks for password very frequently if it is configured for specific connection path, e.g. slow and fast network connections. There could be other issues as well e.g. Password expiration, wrong password attempts etc.…., but the one shown below is more common.

Scenario: I am having the same problem with outlook 2013

Solution: To resolve this, you may try the following:

Please verify if your password is expired or if you are typing the password correctly while attempting to reconnect to outlook emails.

Alternatively,

Open Outlook > Go to File > Account and Settings > Account Settings > Select Your Outlook account > Click on Change > More Settings > Connections > Exchange Proxy Settings > Remove check marks from below highlighted options > Click Ok > Click Ok...

Cheers, Please write me back if you have any query or feedback!

Methods in Python Lists

Lists Methods

The List data type has some important methods to make it useful.

append( ) : Add or append an item to the end of the list.

Syntax: list.append( item )

list = [1, 2, 3, 4, 5, 6]

list.append( 7 )

print( list )

Output:

[1, 2, 3, 4, 5, 6, 7]

extend( ) : Extend the list by appending all the items of the other list

Syntax: list_1.extend( list_2 )

list_1 = [1, 2, 3, 4, 5, 6]

list_2 = [7, 8, 9, 10, 11]

list_1.extend( list_2 )

print( list_1 )

Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

insert( ) : Insert an item at the given position. If position is not provided then the

item will be added to end of the list.

Syntax: list_1.insert( pos, item )

list_1 = [1, 4, 9, 25, 36]

list_1.insert( 3, 16 )

print( list_1 )

list_1.insert( 49)

print( list_1 )

Output:

[1, 4, 9, 16, 25, 36]

[1, 4, 9, 16, 25, 36, 49]

remove( ) : Remove the first occurrence of the given item in the list. If no such item in

the list exists then, it raises ValueError.

Syntax: list_1.remove( item )

list_1 = [1, 4, 9, 25, 36]

list_1.remove( 25 )

print( list_1 )

Output:

[1, 4, 9, 36]

pop( ) : Pop off the item at the given index in the list and return it. If index is not

provided then, it pops off the last item and returns it.

Syntax: list_1.pop( [index] )

list_1 = [1, 4, 9, 25, 36]

list_1.pop( [2] )

Output:

9

count( ) : Return the number of times the given item appears in the list.

Syntax: list_1.count( item )

list_1 = [1, 4, 9, 25, 36, 25]

list_1.count( 25 )

Output:

2

clear( ) : Empty the whole list.

Syntax: list_1.clear(  )

list_1 = [1, 4, 9, 25, 36, 25]

list_1.clear( )

print( list_1 )

Output:

[ ]

sort ( ) : Sort the list items in the preferred order.

Syntax: list_1.sort( key = None, reverse = False  )

list_1 = [5, 1, 4, 6, 0, 8]

list_1.sort( )

print( list_1 )                            // sorts in ascending order

list_1.sort( reverse = True )

print( list_1 )                          // sorts in descending order 

Output:

[0, 1, 4, 5, 6, 8]

[8, 6, 5, 4, 1, 0]

reverse( ) : Reverse the items of the list in place.

Syntax: list_1.reverse(  )

list_1 = [1, 4, 9, 25, 36]

list_1.reverse( )

print( list_1 )

Output:

[36, 25, 9, 4, 1]